1) Which reaction converts an atom of one element to
an atom of another element?
a) combustion b) polymerisation
c) transmutation d) Saponification
2) Radioactive Cobalt-60 is used in radiation therapy
treatment. Cobalt-60 undergoes beta decay. This type of nuclear reaction is
called __________
a) artificial transmutation b) natural transmutation
c) nuclear fission d)
nuclear fusion
3) Which is most effective for artificial
transmutation?
a) Proton b) Deuteron
c)
Helium nuclei d) Neutron
Answer: Neutrons possess no charge at all and are considered to be the best
projectiles.
4) For artificial transmutation of nuclei, the least
effective one is
a) Proton b) Deuteron
c) Alpha particles d)
Neutron
Answer: Due to heavy mass, alpha particles cannot easily pass through matter.
5) The given nuclear reaction is X + 0n1
→ 3Li7 + 2He4.
The particle represented by X is __________
a) 4Li9 b) 5B10 c) 5Be10 d) 6C10
Answer: 5B10+ 0n1 → 3Li7 + 2He4 Here Z
and A are balanced.
6) 13Al28 is transferred into 15P31
and neutron when it is bombarded with suitable projectile. The projectile used
is _________
a) Proton b) Deuteron
c) Alpha particle d)
Neutron
Answer: 13Al28 + 2He4 → 15P31 + 0n1
Here Z and A are balanced.
7) Artificial elements have been prepared by
bombardment reactions in high energy accelerators. Find the mass number of
element X produced in the given reaction.
95Cf249 + 7N15
→ 105X + 4 0n1
a) 261 b)
260 c) 264 d) 257
Answer: A= (249+15-4) = 260
8) (JEE 2011 Question) Bombardment of aluminium
by alpha particle leads to its artificial disintegration in two ways, (i) and
(ii) as shown below. Products X, Y and Z respectively are:
a) Proton, Neutron, Positron b) Neutron, Positron, Proton
c) Proton, Positron, Neutron d) Positron, Proton, Neutron
Answer: For X, 13Al27 + 2He4
→ 14Si30 + 1H1
For Y, 13Al27
+ 2He4 → 15P30 + 0n1
For
Z, 15P30 → 14Si30
+ 1e0
9) (JEE 2013 Question)
In the nuclear
transmutation, 4Be9 + X → 4Be8 + Y.
(X,Y) is (are)
a) (γ,n) b)
(P,D) c) (n,D) d) (γ,D)
Answer: A and B
4Be9 + γ → 4Be8 + 0n1
4Be9 + 1H1 → 5B10 → 4Be8 + 1H2
10) (JEE 2012 Question) The periodic table
consists of 18 groups. An isotope of copper, on bombardment with protons,
undergoes a nuclear reaction yielding element X as shown below. The group to
which, element X belongs in the periodic table is ______
29Cu63 + 1H1 → 6 0n1 + 2He4
+ 2 1H1 + X
Answer: Group 8 element : 26Fe52
Element X : Atomic number Z = (29+1)-(0+2+2)=26
Mass
number A = (63+1)-(6+4+2)=52
Hence X is 26Fe52. It belongs to
group 8.